A sample of gas has a volume of `8.5dm^(3)` at an unknown temperature. When the sample is submered in ice water at `0^(@)C`, its volume gets reduced to `6.37dm^(3)`. What is its initial temperature?

Explanation

`V_(1)=8.5dm^(3)" "V_(2)=6.37dm^(3)`
`T_(1)=?T_(2)=0^(@)C=273K`
`(V_(1))/(T_(1))=(V_(2))/(T_(2))`
`V_(1)xx((T_(2))/(V_(2)))=T_(1)`
`T_(1)=8.5cancel(dm^(3))xx(273K)/(6.37cancel(dm^(3)))`
`T_(1)=364.28K`