A neon-dioxygen mixture contains `60.8` dioxygen and `167.5 g` neon. If pressure of the mxiture of gases in the cylinder is 20 bar, what is the partial pressure of dioxygen and neon in the mixture ?

Explanation

Mass of neon `=167.5`
Mass of dioxygen `=60.8g`
Pressure= 20 bar
sol . No of moles of dioxygen `=(60.8g)/(32 g"mol")=1.9 mol`
No. of moles of neon `=(167.5g)/(20 "g mol")=8.375"mol"`
Mole fraction of dioxygen
`=(1.9)/(1.9+8.375)=(1.9)/(10.275)=0.185`
Mole fraction of neon `=(8.375)/(1.9+8.375)=(8.375)/(10.275)=0.815`
Partial pressure of gas = Mole fraction `xx` total pressuren
Partial pressure of dioxygen `=0.185xx20=3.7` bar
Partial pressure of neon `=0.815xx20= 16.3` bar