The vanderwaal's constant a=2.095 "lit"^...

The vanderwaal's constant `a=2.095 "lit"^(-2) atm "mol"^(-1) and b=0.0189 "lit mol"^(-1)` respectively. Calculate the inversion temperature.

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Given:
`a=2.095 "lit"^(2) "atm mol"^(-)`
`R=0.821 dm^(3) "atm lit" K^(-1) "mol"^(-1)`
`b=0.0189 "lit mol"^(-1)`
Sol `T_(i) =(2a)/(Rb)`
`=(2xx2.095)/(0.821xx0.0189)=2700.28 K`
`T_(1) =2700.28 K`

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