If a scuba diver takes a breath at the surfae filling his lungs with `5.82 dm^(3)` of air what volume will the air in his lungs occupy when he drives to a dept where the pressure is `1.92 atm`. (aausme temperature is constant and the pressure at the surface ix excatly)

Explanation

Given data `P_(1)= 1 atm V_(1)= 5.82dm^(3)`
According to Boyles law,
`P_(1)V_(1)=P_(2)V_(2)`
`V_(2)=(P_(1)V_(1))/(P_(2))`
`V_(2)=(1 atm xx5.82 dm^(3))/(1.92 atm)`
`V_(2)=3.031 dm^(2)`