If the wather balloon at a pressure `0.0965 atm`. At ground level has a valume of `10.0m^(3)`. What will be the pressure at an altitude of 5300 m where its volume is `20.0 m^(3)?`

Explanation

Pressure of gas at ground level `P_(1)=0.965` atm
Volume of the gas at ground level `V_(1)=10.0 m^(3)`
Volume of the gas at an attitude of `5300 m V_(2)=20.0m^(3)`
Pressure of the gas at an altitude of `5300 P_(2)=?`
According to Boyle's law `T_(1)V_(1) =P_(2) V_(2)`
`0.965xx 10=P_(2)xx 20.0`
`P_(2)=(0.0965xx10.0)/(20.0)=0.048
5`
Pressure of the gas at an attitude of 5300 m
`P_(2)=0.0485 atm`