At what temperature would `4.285g `o foxygen gas `O_(2)` exert a pressure of `1.21` atm. In a `2.15 dm^(3)` flask.

Explanation

Mass of oxygen `=4.25g `
No. of moles of oxygen `=(4.25)/(32)=0.1328` moles
Pressure `P=1.21` atm, volume `V=2.15 dm^(3)`
According to ideal gas eqation
`PV= nRT`
`T=(PV)/(nR)=(1.21xx2.15)/(0.3128xx0.0821)`
`:.R` is the gas constant
`R=0.0821 L "atm K mol"^(-1)`
`=(2.6015)/(0.0109)=238K`