The equilibrium constant of a reaction is 10, what will be the sign of `DeltaG` ? Will this reaction be the sign of `DeltaG` ? Will this reaction be spontaneous ?

Explanation

`DeltaG=-2.303 Rt 10 g K_(eq)`
`K_(eq) =10`
`:.DeltaG^(@)=-Ve` value , so the reaction will be spontaneous.