Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of `2L " at "25^(@)C` and normal pressure.

Explanation

n = 2 moles
`V_(i) =500m l =0.5 "lit"`
`V_(f) =2"lit"`
`T=25^(@)C =298K`
`W=-2.303 nRTlog.((V_(f))/(V_(i)))`
`W=--2.303xx2xx8.314xx298xxlog((2)/(0.5))`
`W=--2.303xx2xx8.314xx298xxlog(4)`
`W=--2.303xx2xx8.314xx298xx0.6021`
`W=-6871J`
`W=-6.871 KJ`