1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature , absorbs heat 3710 J and expands to 2 litres . Calculate the entropy changes in expansion process.

Explanation

n = 1 mole
P = 4.1 atm
T = ?
`q=3710 J`
`DeltaS=(q)/(T)`
`DeltaS=q/(((PV)/(nR)))`
`DeltaS=(1xx0.082 " lit atm "K^(-1)xx3710J)/(4.atmxx2" lit ")`
`DeltaS=37.10 JK^(-1)`