30.4 KJ is required to melt one mole of sodium chloride . The entropy change during melting is `28.4JK^(-1) mol^(-1)` .Calculate the melting point of sodium chloride .

Explanation

`DeltaH_(f)(NaCl)=30.4 KJ =30400 J "mol"^(-1)`
`DeltaS_(f)(NaCl)=28.4 JK^(-1) "mol"^(-1)`
`T_(f)=?`
`DeltaS_(f)=(DeltaH_(f))/(T_(f))`
`T_(f)=(DeltaH_(f))/(DeltaS_(f))`
`T_(f)=(30400Jmol^(-1))/(28.4 J K^(-1)" mol"^(-1))=1070.4 K.`