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The heat of combustion of solid naphthal...

The heat of combustion of solid naphthalene. `(C_(10)H_(10))` at constant volume was `-4984kJmol^(-1) " at " 298K.` Calculate the value of enthalpy change. Given:
`C_(10)H_(8_((s)))+120_(2_((g)))rarr10CO_(2_((g)))+4H_(2)O_((l)),DeltaU=-4984 kJ.mol^(-1)`
`DeltaU=-4984 kJmol^(-1),R=8.314JK^(-1)mol^(-)`
`T=298K`

Text Solution

Verified by Experts

`Deltan=10-12=-2mol`
`DeltaH=DeltaU+Rt(Deltan)`
`=-4984xx10^(3)J+8.314Jk^(-1)mol^(-1)xx298kxx(-2)mol.`
`=-4984000J-4955.144J =-4988955.144J`
`DeltaH=-4988.955kJ`
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