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If K(b) and K(f) for a reversible reacti...

If `K_(b)` and `K_(f)` for a reversible reactions are `0.8xx10^(-5)` and `1.6xx10^(-4)` respectively, the value of the equilibrium constant is,

A

20

B

`0.2xx10^(-1)`

C

`0.05`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Equilibrium constant, `K_(C)` is equal to `K_(b)//k_(f)`
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