The equilibrium constants of the following reactions are :
`N_(2)+3H_(2)hArr2NH_(3)" "," "K_(1)`
`N_(2)+O_(2)hArr2NO" "," "K_(2)`
`H_(2)+1//2O_(2)hArrH_(2)O" "," "K_(3)`
The equilibrium constant (K) for the reaction ,
`2NH_(3)+5/2O_(2)overset(K)(hArr)2NO+3H_(2)O`, will be

Options

A. `K_(2)^(3)(K_(3))/(K_(1))`
B. `K_(1)(K_(3)^(3))/(K_(2))`
C. `K_(2)(K_(3)^(3))/(K_(1))`
D. `K_(2)(K_(3))/(K_(1))`

Answer

C

Explanation

`K_(C)` is equal to `[c][D]//[A][B]`.