One mole of `PCl_(5)` is heated in one litre closed container. If 0.6 mole of chlorine is found at equilibrium, calculate the value of equilibrium constant.

Explanation

Given that `[PCl_(5)]_("initial")=("1 mole")/("1 dm"^(3))`
`" "[Cl_(2)]_(eq)=0.6" mol dm"^(-3)`
`PCl_(5)hArrPCl_(3)+Cl_(2)`
`[PCl_(3)]_(eq)=0.6" mole dm"^(-3)`
`[PCl_(5)]_(eq)=0.4" mole dm"^(-3)`
`:.K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=(0.6xx0.6)/(0.4)`
`K_(c)=0.9`.