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Two moles of N(2) and two moles of H(2) ...

Two moles of `N_(2)` and two moles of `H_(2)` are taken in a closed vessel of 5 litre capacity and suitable conditions are provided for the reaction. When the equilibrium is reached, it is found that a half mole of `N_(2)` is used up. The equilibrium concentration of `NH_(3)` is

A

0.2

B

0.4

C

0.3

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
A

Equilibrium concentration
`=("No. of moles at equilibrium")/("Volume")=(1)/(5)=0.2`
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