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The value of equilibrium constant of rea...

The value of equilibrium constant of reaction `HI_((g))hArr1/2H_(2(g))+1/2I_(2(g))` is 8.0. The equilibrium constant of the reaction , `H_(2(g))+I_(2(g))hArr2HI_((g))` will be

A

`1/8`

B

`1/16`

C

`16`

D

`1/64`

Text Solution

Verified by Experts

The correct Answer is:
D
Formation `alpha(1)/("Dissociation")`
Then when the reactants & products concentration are doubled, hence equilibrium constant is also doubled.
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