Write the relationship between equilibrium constant and enthapy.

Explanation

The value of equilibrium constant changes with change in temperature.
If `K_(1)` and `K_(2)` are equilibrium constants at temperature `T_(1)` and `T_(2)`.
`DeltaH` - Heat of reaction at constant pressure.
Then,
`"log"(K_(2))/(K_(1))=(DeltaH)/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`