Calculated the molality of a solution containing 7.5 g of glycine ` (NH_2 -CH_2 -COOH) ` dissolved in 500g of water

Explanation

` "Molality " =( "No of moles of solute ")/( " Mass of the solvent ( in kg ) ") `
No. of moles of glycine =` ( "mass of glycine ")/( " molar mass of glycine ") `
` = ( 7.5 )/( 75) =0.1 `
Molality =`( 0.1)/( 0.5 kg ) ` 0.2 m