Calculate the volume of 1.5 N ` H_2SO_4 ` completely neturalized by 35.8 mL of
` 2.5MBa(OH_2) `

Explanation

` 2.5M Ba(OH)_2`
Normality = Molality x Acidiliy
` " " = 2.5xx 2 = 5N`
Volume of `H_2SO_4 (V_1) " " xml `
Normality of` H_2SO_4 (N_1) " " =1.5N`
Volume of ` Ba(OH)_2(V_2) " " = 25.8ml`
Normality of ` Ba(OH)_2(N_2) " "= 5N`
According to volumetric law
` " "V_1N_1 =V_2N_2`
` " " x xx 1.5 =38.5xx 5`
` " " x=( 38.5xx 5)/( 1.5) `
` " " x= 119.3ml `