Explain how would you prepare the following dilute solution from more condentrated solution
(a) ` 5L "of" 6.00 M H_2SO_4 ` from 18.0 M` H_2SO_4 `
(b) 250 mL of 0.5 M ` CaCl_2 ` form ` 3.0 M CaCl_2 ` solution
© ` 0.2 N H_2SO_4 500 mL ` from 3.0 M `H_2SO_4`

Explanation

`5L " of" 6.00 MH_2SO_4 `from 18.0 M`H_2SO_4 `
Given ` V_1 =5L, V_2 =?`
` W_1 = 6M ,N_2 = 18. 0M`
According to volumetric law M
` V_1 N_1 =V_2N_2 `
` 5xx =V_2 xx 18 `
` V_2 = ( 5xx 6 ) /( 18 ) =(30 )/( 18 ) = 1.66L `
(b) `V_1 =250 mL V_2 =? `
`N_1 = 0.5 M " " N_2 = 3.0 M `
According to voumetric law
` V_1N_! =V_2N_2 `
` 250xx 0.5 = V_2 xx 3.0`
` V_2 =( 250xx0.5)/( 3.0)= 4.166 mL `
(C) Given
` V_1 =500 mL " " V_2=? `
` N_1=0.2N " "N_2 = 3.0 M= 6N`
` V_1N_1 =V_2N_2`
` 500xx 0.2 =V_2 xx 6`
` V_2 =( 500 xx 0.2)/( 6) =16.66mL`