Calculate the molefraction of each component in a mixture containing 40 mass percent of toluene in ` CHCl_3`

Explanation

Mass of toluene `= 40g : `mol mass of toluene= 92
Mass of ` CHCl_3 = 60g : ` Mol mass of ` CHCl_3 = 119.3`
No . Of moles of toluene `" " ( 40)/( 92) " " =0.4397`
No. of moels of ` CHCl_3" " =( 60)/( 119.3) `
Total moles ` 0.4347+0.5029 = 0.9376`
Mole fraction of toluene ` = ( 0.4347)/( 0.9376) `
` " " = 0.4636`
Mole fraction of ` CHCl_3" "= ( 0.5029)/( 0.9376) `
` " " = 0.5363`