Calculate the boiling point of a solution which is prepared by dissolving 68.4g of solute B in one kilogram of water . (Molar mass of solute B is 342 g ` mol^(-1) T_b=373.1 K and K_b `(water ) = 0.52 K ` kg mol ^(-1) `

Explanation

` W_1 " " 1kg `
` W_2 " "= 68.4g`
`M_2 " " =342 g mol^(-1) `
` T_b " " =373.1K`
` K_b " " = 0.52K.kg mol ^(-1) `
` T-T_b " " = K_b m `
`m " "= 0.2`
` T-T^(@) " " K_bxxm `
` T-T^(@) =0.52 xx 0.2`
` T-T^(@) =0.104`
` T-373.1 =0.101`
`T =" " 0.101+373.1`
` T" "= 373.204`