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Bond order of a species is 2.5 and the n...

Bond order of a species is `2.5` and the number of electons in its bonding molecular orbital is found to be 8 The no. of electons in its antibonding molecular orbital is

A

three

B

four

C

zero

D

can not be calculated with the given information.

Text Solution

Verified by Experts

The correct Answer is:
a
Bond order = (No. of bonding electron - No of anti-bonding electrons)/2
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