Draw MO diagram of CO and calculate its bond order .

Explanation

Bonding in some heteronuclear di - atomic molecules :
Molecular orbital diagram of Carbon monoxide molecule (CO)
Electronic configuration of C atom `1s^(2) 2s^(2) 2p^(2)`
Electronic configuration of O atom `1s^(2) 2s^(2) 2p^(4)`
Electronic conguration of CO molecule
`sigma_(1s)^(2), sigma_(2s)^(**2) , sigma_(2s)^(2), sigma_(2s)^(**2), pi_(2py)^(2), pi_(2pz)^(2), sigma_(2px)^(2)`
Bond order ` = (N_(b) - N_(a))/2 = (10 - 4)/ 2 = 3`
Molecule has no unpaired electrons hence it is diamagnetic.