Discuss the formation of `N_(2)` molecule using MO theory

Explanation

Molecular orbital diagram of nitrogen molecule `(N_(2))`:

(i) Electronic configuration of N atom `1s^(2) 2s^(2) 2p^(3)`
(ii) Electronic configuration of `N_(2)` molecule
`sigma_(1s)^(2), sigma_(1s)^(**2) , sigma_(2s)^(2), sigma_(2s)^(**2), pi_(2py)^(2), pi_(2pz)^(2) , sigma_(2px)^(2)`
(iii) Bond order ` = (N_(b) - N_(a))/2 = (10 -4)/ 2 = 3`
(iv) Molecule has no unpaired electrons hence it is diamagnetic.