Calculate the total number of electrons present in 17g of ammonia.

Explanation

No. of electrons present in one ammonia `(NH_(3))` molecule (7+3)=10
No. of moles of `NH_(3)=`
`(Mass )/("Molar mass")=(17g)/(17gmol^(-1))=1mol`
No .of molecules present in 1 mol of `NH_(3)=6.023xx10^(23)`
No. of electrons present in 1 mol of `NH_(3) `
`" "=10xx6.023xx10^(23)`
`" "=6.023xx10^(24)`