Define Molarity. If 5.6 g of KOH is present in 250 ml of the solution, calculate the molarity of the solution.

Explanation

''The number of moles of solute dissolved in one litre of the solvent'' is called as Molarity of the solution.
Molarity (M) `=("number of moles of solute")/("Volume of the solvent in Litres")`
If 5.6 g of KOH is present in 250 ml of the solution Number of moles of KOH `= (5.6 g)/(56 mol^(-1))=0.1` moles
Molarity (M) `= ("0.1 moles")/("0.4 Lit")=0.25 "mol Lit"^(-1)` (or) 0.25 M.