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An element 'A' occupies group number 15 ...

An element 'A' occupies group number 15 and period number 3. It reacts with chlorine to give B which further reacts with chlorine to give C at 273 K . Both B and C are chlorinating agents for organic compounds. C is a better chlorinating agent because it chlorinates metals also. B reacts with `SO_(3)` and reduces it to `SO_(2)`. B has a pyramidal shape. C has trigonal bipyramidal shape by `sp^(3)d` hybridisation. Identify the element A and the compounds B and C. Write the reactions.

Text Solution

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The element which occupies group number 15 and period number 3 is phosphorus. Therefore A is phosphorus. Phosphorus reacts with chlorine to give `PCl_(3)`. Therefore compound B is phosphorus trichloride and it has a pyramidal shape.
`P_(4)+6Cl_(2) rarr 4PCl_(3)`
`PCl_(3)` further reacts with `Cl_(2)` to give `PCl_(5)`. Therefore, the compound C is phosphorus pentachloride and it has a trigonal bipyramidal shape .
`PCl_(3)+Cl_(2) rarr PCl_(5)`
Thus, A = Phosphorus
`" "` B = Phosphorus trichloride `(PCl_(3))`
`" "` C = Phosphorous penta chloride `(PCl_(5))`
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