Calculate the magnetic moment of `Fe^(3+)` ion (atomic no. of Fe=26)

Explanation

`Fe^(3+)` has the electronic configuration `[Ar] 4s^(0) 3d^(5)`
It is unpaired electron
`mu= sqrt(n(n+2))`
`= sqrt(5(5+2)) = sqrt(35) = 5.9 BM`