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The solubility of BaSO4 in water is 2.42...

The solubility of `BaSO_4` in water is `2.42xx10^(-3)gL^(-1)` at 298K. The value of its solubility product `(K_(sp))` will be, (Given molar mass of `BaSO_4=233g mol^(-1)`)

A

`1.08xx10^(-14)mol^2 L^-2`

B

`1.08xx10^-12 mol^2 L^-2`

C

`1.08 xx10^(-10)mol^2 L^-2`

D

`1.08xx10^-8 mol^2 L^-2`

Text Solution

Verified by Experts

The correct Answer is:
C
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