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Using Gibb's free energy change, AG^@ = ...

Using Gibb's free energy change, `AG^@ = 57.34 kJ mol^(-1)`, for the reaction, `X_2 Y_((s)) hArr2X^+ +Y_((aq)^3)^(2-)` calculate the solubility product of `X_2 Y` in water at 300 K `(R=8.3 JK^(-1) Mol^(-1))`

A

`10^(-10)`

B

`10^(-12)`

C

`10^(-14)`

D

can not calculated from the given data.

Text Solution

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The correct Answer is:
A
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