Define the ionic product of water. Give its value at room temperature.

Explanation

Ionic product of water (kw) is given by the product of concentration of hydronium `(H_3 O^+)` and hydroxide `(OH^-) "ion"^-.`
`2H_2O hArr H_3O^++OH^-`
`k_(aq)=([H_3O^+][OH^-])/([H_2O]^2)`
Since water is a solvent and is taken in excess, change in concentration due to dissociation is negligible.
`therefore "Keg"=[H_2O]^2=[H_3O^+][OH^-]=kW` At `298 k (25^@ C) kw=1xx10^(-14) mol^2 dm^(-6)`.