At a particular temperature, the `K_(w)` of a neutral solution was equal to `4xx10^(-14)` . Calculate the concentration of `[H_3O^+] and [OH^-]`.

Explanation

Given solution is neutral
`therefore [H_3 O^+]=[OH^-]`
Let `[H_3 O^+]=x ,` then `[OH^+]=x`
`K_(sp)=[H_3O^+][OH^-]`
`4xx10^-14=x.x`
`x^2=4xx10^(-14)`
`x=sqrt(4xx10^(-14))=2xx10^(-7)`