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K(b) for NH4 OH is 1.8xx10^(-5). Calcula...

`K_(b)` for `NH_4 OH` is `1.8xx10^(-5).` Calculate the percentage of ionisation of `0.06 M` ammonium hydroxide solution.

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`alpha=sqrt((K_(b))/( C))=sqrt((1.8xx10^(-5))/(6xx10^(-2))`
`=sqrt(3xx10^(-1))`
`sqrt(1.732xx10^(-2))`
`=(1.732)/(100)=1.732 %`
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