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Calculate the ionisation constant for th...

Calculate the ionisation constant for the conjugate base of HF. Ionisation constant of HF at 298K is `6.8xx10^(-4)`.

Text Solution

Verified by Experts

The conjugate base of HF is `F^-`
For `F^-. K_b=(K_w)/(K_a)=(10^(-14))/(6.8xx10^(-4))`
`=1.47xx10^(-11)`
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