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0.1M copper sulphate solution in which c...

0.1M copper sulphate solution in which copper electrode is dipped at `25^(@)C`. Calculate the electrode potential of copper.
[Given: `E_(Cu^(2+)"|"Cu)^(@)=0.34`]

Text Solution

Verified by Experts

Give that
` [Cu^(2+)] = 0.1M `
` E_(Cu^(2+|Cu^(@) = 034 `
` E_("cell") = ? `
Cell reaction is
` Cu_(aq)^(2+) + 2e^(-) to Cu_((s))`
` E_("cell") = E^(@) - ( 0.0591)/n log ([Cu])/([Cu^(2+)])`
` = 0.34 (0.0591)/2 log 1/(0.1)`
= 0.34 - 0.0294
0.31 V
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