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The voltage across a wire is (100+-5)v a...

The voltage across a wire is `(100+-5)v` and the current passing through it is `(10+-0.2)A`.

Text Solution

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Voltage `V=(100+-5)V`
Curent I`=(10+-0.2)A`
Resistance `R=?`
Then resistance R is given by Ohm's law
`R=V/I=100/10=10 Omega`
`(Delta)/R=((DeltaV)/V+(DeltaI)/I)`
`DeltaR=((DeltaV)/V+(Delta)/I)r=(5/100+0.2/10)xx10`
`=(0.05+0.02)xx10=0.07xx10=0.7`
The resistance `R=(10+-0.7)Omega`
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