If mass of an electron is `9.11xxx10^(-31)` kg, how many electrons would weigh in 1 mg?
Given data:
Mass of an electron `=9.11xx10^(-31)kg`
`=9.11xx10^(-31)` kg is the mass of 1 electron

Explanation

`9.11xx10^(-31)kg=9.11xx10^(-31)xx10^(3)g`
`=9.11xx10^(-28)g`
`=9.11xx10^(-25)mg`
1 mg is the mass of `1/(9.11xx10^(-25)mg)` electron `=0.0197xx10^(25)` electrons `=1.097xx10^(24)` electrons
`=1.097xx10^(24)` electrons would length in 1 mg.