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Find the speed of the projectile when it...

Find the speed of the projectile when it hits the ground.

Text Solution

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The speed of the particle when it reaches the ground is `v=sqrt(u^(2)+2gh)`
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Knowledge Check

  • An object falls from a height h (hltltR) .the speed of the object when it reaches the ground is

    A
    `(1)/(2)"gt"^(2)`
    B
    `sqrt"gt"`
    C
    gh
    D
    `sqrt(2gh)`

  • Two objects of masses m_(1) and m_(2) fall from the heights h_(1) and h_(2) respectively . The ratio of the magnitude of their momenta when they hit the ground is :

    A
    `sqrt((h_(1))/(h_(2)))`
    B
    `sqrt((m_(1)h_(1))/(m_(2)h_(2)))`
    C
    `(m_(1))/(m_(2))sqrt((h_(1))/(h_(2)))`
    D
    `(m_(1))/(m_(2))`

  • Two objects of masses m_(1) and m_(2) fall from the heights h_(1) and h_(2) respectively . The ratio of the magnitude of their momenta when they hit the ground is :

    A
    `sqrt((h_(1))/(h_(2)))`
    B
    `sqrt((m_(1)h_(1))/(m_(2)h_(2)))`
    C
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    D
    `(m_(1))/(m_(2))`

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