A gun of mass M fires a bullet of mass m with maximum speed v. G.T. `m lt M`. The kinetic energy of the gun will be

Options

A. `(1)/(2)mv^(2)`
B. `(1)/(2)Mv^(2)`
C. more than `(1)/(2)mv^(2)`
D. less than `(1)/(2)mv^(2)`

Answer

D

Explanation

By conservation of momentum `mv = Mv rArr`
` v = (mv)/(M)` Kinetic energy of the gun `= (1)/(2)mv^(2)`
`=(m)/(M)((1)/(2)mv^(2))lt (1)/(2)mv^(2)`