A particle of mass `m_(1)` is moving with a velocity v, and another of mass `m_(2)` is moving with velocity `v_(2)`. Both of them have the some momentum but their kinetic energies are `E_(1)` and `E_(2)` respectively. If `m_(1) gt m_(2)` then

Options

A. `E_(1)lt E_(2)`
B. `(E_(1))/(E_(2))=(m_(1))/(m_(2))`
C. `E_(1)gt E_(2)`
D. `E_(1)=E_(2)`

Answer

A

Explanation

`K.E. = (p^(2))/(2m)` For same p, E `alpha (1)/(m) , (E_(1))/(E_(2))=(m_(2))/(m_(1))`,
`m_(1)gt m_(2) therefore E_(1)lt E_(2)`