A particle of mass 'm' moving with velocity 'v' collides with a mass `m_(2)` at rest, then they get embedded. At the instant of collision, velocity of the system

Options

A. increases
B. decreases
C. remains constant
D. becomes zero

Answer

C

Explanation

By conservation of momentum `m_(1)u_(1)+m_(2)xx 0[u_(2)=0]`
`= (m_(1)+m_(2))v`
`v = (m_(1)u_(1))/(m_(1)+m_(2))` As `(m_(1))/(m_(1)+m_(2))lt 1`, so , `u_(1)gt v`.
velocity decreases at the time of collision.