A circket ball falls from a height of 40...

A circket ball falls from a height of 40 m. What is the velocity with which the ball hits the ground ?

`40 ms^(-1)`

`20 ms^(-1)`

`16 ms^(-1)`

`28 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

When it hits the ground kE = pE
`(1)/(2)mv^(2)=mgh`
`v = sqrt(2gh)=sqrt(2xx9.8xx40)`
`=sqrt(784)=28ms^(-1)`.

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