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Find the moment of inertia of a hydrogen...

Find the moment of inertia of a hydrogen molecule about an axis passing through its center of mass and perpendicular to the interatomic axis. Given : mass of hydrogen atom `1.7 xx 10^(-27)` kg and inter atomic distance is equal to `4 xx 10^(-10)` m.

Text Solution

Verified by Experts

M.I. of a `H_(2)` molecule about an axis passing through Center of Mass.

`I = 2m. (a^(2))/(4)`
`I = (2 xx 1.7 xx 10^(-27) xx (4 xx 10^(-10))^(2))/(4)`
`= ((3.4 xx 10^(-27))xx (16 xx 10^(-20)))/(4)`
`= 13.6 xx 10^(-47) (or) 1.36 xx 10^(-46) kg" "m^(2)`
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