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The angular momentum of a rotating body ...

The angular momentum of a rotating body is doubled, its K.E. of rotation becomes

A

Two times

B

Four times

C

Halved

D

Eight times

Text Solution

Verified by Experts

The correct Answer is:
b

`L = I omega" "K.E. = (1)/(2) I omega^(2) = E`
`(L_(1))/(L) = sqrt((E_(1))/(E))" "I omega^(2) = 2E" "(Iomega)^(2) = 2EI`
`2 = sqrt((E_(1))/(E))" "therefore" "E_(1) = 4E`
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