Explain the freely falling apple on Earth using the concept of gravitational potential V(r)?
Explain the freely falling apple on Earth using the concept of gravitational potential V(r)?
Text Solution
Verified by Experts
The gravitational potential V (r) at a point of height h from the surface of the Earth is given by,
`V(r = R + h) = (GM_E)/((R + h))`
The gravitational potential V(r) on the surface of Earth is given by
`V(r = R) = ( GM_E)/R`
Thus we see that
`V (r = R) < V(r = R + h)`
`V(r = R + h) = (GM_E)/((R + h))`
The gravitational potential V(r) on the surface of Earth is given by
`V(r = R) = ( GM_E)/R`
Thus we see that
`V (r = R) < V(r = R + h)`
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Knowledge Check
A body of mass m is placed on Earth surface which is taken from Earth surface to a height h = 3R, then change in gravitaional potential energy is:
A body of mass m is placed on Earth surface which is taken from Earth surface to a height h = 3R, then change in gravitaional potential energy is:
A
`(1)/(4)mgR`
B
`(2)/(3)mgR`
C
`(3)/(4)mgR`
D
`(1)/(2)mgR`
A body of mass m is placed on Earth surface which is taken from Earth surface to a height h = 3R, then change in gravitaional potential energy is:
A body of mass m is placed on Earth surface which is taken from Earth surface to a height h = 3R, then change in gravitaional potential energy is:
A
`(1)/(4)mgR`
B
`(2)/(3)mgR`
C
`(3)/(4)mgR`
D
`(1)/(2)mgR`
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