A Geo-stationary satellite bits around the earth in a circular of radius 36, 000 km then what will be the time period of a spy satellite orbiting a few hundred km above the earth's surface `(R_("earth") = 6400 km)`

Explanation

`T^(2) prop R^(3) , R_(E) = 6400 km`
`(T^2)/((24)^2) = ((6400)/(3600))^(2)or T = 1.7 h`
for the spy satellite, R is slightly greater than `R_(E)`, So `T_(s) > T or T_(s) = 2h`.