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The mass and diameter of a planet are tw...

The mass and diameter of a planet are twice those of the earth. What will be the time period of that pendulum on this planet which is a seconds pendulum on the earth.

Text Solution

Verified by Experts

`g = (GM)/(R^2) and T = 2pi sqrt(l/g) = 2S`
`" "`[For second pendulum]
`mu` and R are doubled
`g' = (G(2mu))/((2R)^2) = g/2`
`T' = 2pi sqrt(l/((g)/(2))) = sqrt(2) T`
` 2 sqrt(2)s`.
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