A cappilary of diameter d mm is dipped in water such that the water rises to a height of 30 mm. If the radius of the capillary is made `((2)/(3))` of its previous value, then compute the height up to which water will rise in the new capillary ?

Explanation

`h prop (1)/(r ) rArr hr = "a constant"`
`h_(1) r_(1) = h_(2) r_(2) = "constant"`
`h_(2) = (h_(1)r_(1))/(r_(2))`
Height of water rises `h_(1) = 30 mm`
Radius of capillary `r_(1) = (d)/(2) mm`
New radius of capillary `r_(2) = (2)/(3)((d)/(2))mm`
`h_(2) = (30 xx d_(2))/(2_(3)(d_(2))) = 45 mm`
`h_(2) = 45mm`