Home
Class 11
PHYSICS
The position vectors particle has length...

The position vectors particle has length 1m and makes `30^(@)` with the x-axis. What are the lengths of the x and y components of the position vector?

Text Solution

Verified by Experts

Length of position vector =OA=1 m=l
x= component of length `l_x=?`
y= component `l_y=?`
`cos 30^(@)= (l_x)/(l)= (l_x)/(1) = l_x`
`:.l_x= cos 30^(@)= (sqrt(3))/(2)`
`sin 30^(@) = (l_x)/(l)=l_y`
`:.l_y = sin 30^(@) = (1)/(2)`
`l_x= (sqrt(3))/(2), l_y= (1)/(2)`.
Promotional Banner

Topper's Solved these Questions

  • GOVT. MODEL QUESTION PAPER - 1

    SURA PUBLICATION|Exercise PART - III|12 Videos
  • GOVT. MODEL QUESTION PAPER - 1

    SURA PUBLICATION|Exercise PART - IV|19 Videos
  • GOVT. MODEL QUESTION PAPER - 1

    SURA PUBLICATION|Exercise PART - IV|19 Videos
  • GOVT. MODEL QUESTION PAPER - 2

    SURA PUBLICATION|Exercise PART - IV (Answer the questions)|12 Videos

Similar Questions

Explore conceptually related problems

What is position vector?

The position vector of the particle is vecr=3t^2 hati+5t hatj+9hatk . What is the acceleration of the particle?

The position vector of a particle is vecr=4t^(2)hati+2thatj+3thatk . The acceleration of a particle is having only

Write down a unit vector in XY - plane making an angle of 30^(@) with the positive direction of x- axis.

Two bodies of mass 1kg and 3kg have position vectors hati+2hatj+hatk and -3hati-2hatj+hatk , respectively.The centre of mass of this system has a position vector.